2 câu trả lời
Đáp án:`+`Giải thích các bước giải:
$a) => x-\dfrac{2}{3}=\dfrac{3}{4}:\dfrac{4}{67}=\dfrac{3}{4}.\dfrac{67}{4}=\dfrac{201}{16}$
$=>x=\dfrac{201}{16}+\dfrac{2}{3}=\dfrac{603}{48}+\dfrac{32}{48}=\dfrac{635}{48}$
Vậy `x=635/48`
$b)=>\dfrac{5}{7}:x=\dfrac{1}{6}-\dfrac{4}{5}=\dfrac{5}{30}-\dfrac{24}{30}=\dfrac{-19}{30}$
$=>x=\dfrac{5}{7}:\dfrac{-19}{30}=\dfrac{5}{7}.\dfrac{30}{-19}=\dfrac{-150}{133}$/
Vậy `x=-150/133`
$ a) ⇒ x-\dfrac{2}{3}=\dfrac{3}{4}:\dfrac{4}{67}=\dfrac{3}{4}.\dfrac{67}{4}=\dfrac{201}{16} $
$ ⇒x=\dfrac{201}{16}+\dfrac{2}{3}=\dfrac{603}{48}+\dfrac{32}{48}=\dfrac{635}{48} $
$ b) ⇒\dfrac{5}{7}:x=\dfrac{1}{6}-\dfrac{4}{5}=\dfrac{5}{30}-\dfrac{24}{30}=\dfrac{-19}{30} $
$ ⇒x=\dfrac{5}{7}:\dfrac{-19}{30}=\dfrac{5}{7}.\dfrac{30}{-19}=\dfrac{-150}{133} $