1. X^2/căn 3x-2. -căn3x-2 = 1-x 2. Căn2x^2-1+căn x^2-3x-2=căn2x^2+2x+3 + Căn x^2-x+2

Giải thích các bước giải:

1,

ĐKXĐ:  \(x \ge \frac{2}{3}\)

\[\begin{array}{l}
\frac{{{x^2}}}{{\sqrt {3x - 2} }} - \sqrt {3x - 2}  = 1 - x\\
 \Leftrightarrow \frac{{{x^2} - {{\sqrt {3x - 2} }^2}}}{{\sqrt {3x - 2} }} + x - 1 = 0\\
 \Leftrightarrow \frac{{{x^2} - 3x + 2}}{{\sqrt {3x - 2} }} + x - 1 = 0\\
 \Leftrightarrow \left( {x - 1} \right)\left( {\frac{{x - 2}}{{\sqrt {3x - 2} }} + 1} \right) = 0\\
 \Leftrightarrow \left[ \begin{array}{l}
x = 1\\
2 - x = \sqrt {3x - 2} 
\end{array} \right.\\
 \Leftrightarrow \left[ \begin{array}{l}
x = 1\\
\left\{ \begin{array}{l}
x \le 2\\
{x^2} - 4x + 4 = 3x - 2
\end{array} \right.
\end{array} \right. \Leftrightarrow \left[ \begin{array}{l}
x = 1\\
x = 6
\end{array} \right.\left( {t/m} \right)
\end{array}\]