Tìm $x$ biết $\dfrac{{ - 1}}{2}:(2x - 1) = 0,2:\dfrac{{ - 3}}{5}$

$a = c$

$a.c = b.d$

$a.d = b.c$

$b = d$

$\dfrac{5}{{35}} = \dfrac{9}{{63}}$

$\dfrac{{63}}{9} = \dfrac{{35}}{5}$

$\dfrac{{35}}{9} = \dfrac{{63}}{5}$

$\dfrac{{63}}{{35}} = \dfrac{9}{5}$

$\dfrac{7}{{12}}$ và $\dfrac{5}{6}:\dfrac{4}{3}$

$\dfrac{6}{7}:\dfrac{{14}}{5}$ và $\dfrac{7}{3}:\dfrac{2}{9}$

$\dfrac{{15}}{{21}}$ và $-\dfrac{{125}}{{175}}$

$\dfrac{{ - 1}}{3}$  và $\dfrac{{ - 19}}{{57}}$        

$\dfrac{5}{{15}} = \dfrac{{ - 9}}{{ - 27}};\,\dfrac{{15}}{5} = \dfrac{{ - 27}}{{ - 9}};\,\dfrac{5}{{ - 9}} = \dfrac{{15}}{{ - 27}};\,\dfrac{{ - 9}}{5} = \dfrac{{ - 27}}{{15}}$

$\dfrac{5}{{15}} = \dfrac{{ - 9}}{{ - 27}};\,\dfrac{{15}}{5} = \dfrac{{ - 27}}{{ - 9}};\,\dfrac{5}{{ - 9}} = \dfrac{{15}}{{ - 27}};\,\dfrac{{ - 9}}{5} = \dfrac{{ - 15}}{{27}}$

$\dfrac{5}{{15}} = \dfrac{{ - 9}}{{ - 27}};\,\dfrac{{15}}{5} = \dfrac{{ - 27}}{9}$

$\dfrac{{15}}{5} = \dfrac{9}{{27}};\,\dfrac{{15}}{5} = \dfrac{{ - 27}}{{ - 9}};\,\dfrac{5}{{ - 9}} = \dfrac{{15}}{{ - 27}};\,\dfrac{{ - 9}}{5} = \dfrac{{ - 15}}{{27}}$

$\dfrac{2}{a} = \dfrac{5}{b}$

$\dfrac{b}{5} = \dfrac{2}{a}$

$\dfrac{2}{5} = \dfrac{a}{b}$

$\dfrac{2}{b} = \dfrac{5}{a}$

$1$

$2$

$0$

$3$