1 câu trả lời
\(y=\dfrac{-3x+2}{x-2}\)
Do \(\lim\limits_{x\to2^+}y=\lim\limits_{x\to2^+}\dfrac{-3x+2}{x-2}=-\infty\)
\(\Rightarrow \) TCĐ: \(x=2\).
\(\lim\limits_{x\to+\infty}y=\lim\limits_{x\to+\infty}\dfrac{-3x+2}{x-2}\)
\(=\lim\limits_{x\to+\infty}\dfrac{-3+\dfrac{2}{x}}{1-\dfrac{2}{x}}=-3\)
\(\Rightarrow \) TCN: \(y=-3\).
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