2 câu trả lời
($x$-$5$)($x$+$6$) = $0$
⇒\(\left[ \begin{array}{l}x-5=0\\x+6 = 0\end{array} \right.\)\(\left[ \begin{array}{l}x=-5\\x=-6\end{array} \right.\)
($x$-$5$)($x$+$6$) = $0$
⇒\(\left[ \begin{array}{l}x-5=0\\x+6 = 0\end{array} \right.\)\(\left[ \begin{array}{l}x=-5\\x=-6\end{array} \right.\)