2 câu trả lời
Đáp án:
`(x- 2).x = (x - 1).(x + 4)`
`-> x.x - 2.x = x.(x + 4) - (x + 4)`
`-> x^2 - 2x = x.x + 4.x - x - 4`
`-> x^2 - 2x = x^2 + 4x - x - 4`
`-> x^2 - x^2 - 2x - 4x + x = -4`
`-> -5x = -4`
`-> x = 4/5`
Vậy `x = 4/5`
$#dariana$
`( x - 2 ) . x = ( x - 1 ) . ( x + 4 )`
`⇒ x . x - 2 . x = x . ( x + 4 ) - 1 . ( x + 4 )`
`⇒ x^2 - 2x = x^2 + 4x - x - 4`
`⇒ x^2 - 2x - x^2 - 4x + x = - 4`
`⇒ ( x^2 - x^2 ) - ( 2x + 4x - x ) = - 4`
`⇒ 0 - 5x = - 4`
`⇒ - 5x = - 4`
`⇒ x = ( - 4 ) : ( - 5 )`
`⇒ x = 4/5`
Vậy `, x = 4/5 .`
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