Tính:1000/1009x2018/2019+19/2018x-2018/2019+1/2020
2 câu trả lời
$\dfrac{1000}{1009}$ x $\dfrac{2018}{2019}$ + $\dfrac{19}{2018}$ x $\dfrac{-2018}{2019}$ + $\dfrac{1}{2020}$
= $\dfrac{1000.2018}{1009.2019}$ + $\dfrac{19.(-2018)}{2018.2019}$ + $\dfrac{1}{2000}$
= $\dfrac{1000.2}{1.2019}$ + $\dfrac{19.(-1)}{1.2019}$ + $\dfrac{1}{2000}$
= $\dfrac{2000}{2019}$ + $\dfrac{-19}{2019}$ + $\dfrac{1}{2000}$
= ($\dfrac{2000}{2019}$ + $\dfrac{-19}{2019}$) + $\dfrac{1}{2000}$
= $\dfrac{2000+(-19)}{2019}$ + $\dfrac{1}{2000}$
= $\dfrac{1981}{2019}$ + $\dfrac{1}{2000}$
Đáp án:
`2019/2020`
Giải thích các bước giải:
`1000/1009\times2018/2019+19/2018\times(-2018)/2019+1/2020`
`=(-2018)/2019\times(1000/1009+19/2018)+1/2020`
`=(-2018)/2019\times(2000/2018+19/2018)+1/2020`
`=(-2018)/2019\times2019/2018+1/2020`
`=(-2018)/2018+1/2020`
`=(-1)+1/2020`
`=(-1)/1+1/2020`
`=(-2020)/2020+1/2020=2019/2020`