Tính:1000/1009x2018/2019+19/2018x-2018/2019+1/2020

2 câu trả lời

$\dfrac{1000}{1009}$ x $\dfrac{2018}{2019}$ + $\dfrac{19}{2018}$ x $\dfrac{-2018}{2019}$ + $\dfrac{1}{2020}$

= $\dfrac{1000.2018}{1009.2019}$ + $\dfrac{19.(-2018)}{2018.2019}$ + $\dfrac{1}{2000}$

= $\dfrac{1000.2}{1.2019}$ + $\dfrac{19.(-1)}{1.2019}$ + $\dfrac{1}{2000}$

= $\dfrac{2000}{2019}$ + $\dfrac{-19}{2019}$ + $\dfrac{1}{2000}$

= ($\dfrac{2000}{2019}$ + $\dfrac{-19}{2019}$) + $\dfrac{1}{2000}$

= $\dfrac{2000+(-19)}{2019}$ + $\dfrac{1}{2000}$

= $\dfrac{1981}{2019}$ + $\dfrac{1}{2000}$

Đáp án:

`2019/2020`

Giải thích các bước giải:

`1000/1009\times2018/2019+19/2018\times(-2018)/2019+1/2020`

`=(-2018)/2019\times(1000/1009+19/2018)+1/2020`

`=(-2018)/2019\times(2000/2018+19/2018)+1/2020`

`=(-2018)/2019\times2019/2018+1/2020`

`=(-2018)/2018+1/2020`

`=(-1)+1/2020`

`=(-1)/1+1/2020`

`=(-2020)/2020+1/2020=2019/2020`

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