Tính phân tử khối sau đây: a)Al2(SO4)3 b)Al2(HPO4)3 c)(CH3COO)2Ca d)CuSO4.5H2O

Đáp án + Giải thích các bước giải:

\(a,\\PTK_{Al_2(SO_4)_3}=27.2+(32+16.4).3\\\qquad \qquad \quad \ \ = 342 \ \ (đvC)\\b,\\PTK_{Al_2(HPO_4)_3}=27.2+(1+31+16.4).3\\\qquad \qquad \qquad \ =342 \ \ (đvC)\\c,\\PTK_{(CH_3COO)_2Ca}=(12+1.3+12+16+16).2+40\\\qquad \qquad \qquad \ \ \ \ \ =158 \ \ (đvC)\\d,\\PTK_{CuSO_4.5H_2O}=64+32+16.4+5.(1.2+16)\\\qquad \qquad \qquad \ \ = 250 \ \ (đvC) \)

Đáp án:

`a)`

`PTK_{Al_2(SO_4)_3} = 27 . 2 + (32 + 16 . 4) . 3 = 342` `đvc`

`b)`

`PTK_{Al_2(HPO_4)_3} = 27 . 2 + (1 + 31 + 16 . 4) . 3 = 342` `đvc`

`c)`

`PTK_{(CH_3COO)_2Ca} = (12 + 3 + 12 + 16 . 2) . 2 + 40 = 158` `đvc`

`d)`

`PTK_{CuSO_4.5H_2O} = 64 + 32 + 16 . 4 + 5 . (2 + 16) = 250` `đvc`