TÌM X BIẾT A) x+1/3=5/6 B)1/3+2/3×x=5/2 C)2/3. (X-1/2)+1/3=-5/6

Đáp án:

a.x+$\frac{1}{3}$=$\frac{5}{6}$ 

x=$\frac{5}{6}$-$\frac{1}{3}$ 

x=$\frac{1}{2}$ 

Vậy x=$\frac{1}{2}$ 

 b.$\frac{1}{3}$+$\frac{2}{3}$*x=$\frac{5}{2}$ 

$\frac{2}{3}$*x=$\frac{5}{2}$-$\frac{1}{3}$ 

$\frac{2}{3}$*x=$\frac{13}{6}$ 

x=$\frac{13}{6}$:$\frac{2}{3}$

x=$\frac{13}{4}$ 

Vậy x=$\frac{13}{4}$ 

`a) x +1/3 = 5/6`

`x = 5/6 - 1/3`

`x = 1/2`

`b)1/3+2/3×x=5/2`

`2/3 × x = 5/2 - 1/3 `

`2/3 × x = 14/6`

`x = 14/6 : 2/3`

`x = 7/2`

`c) 2/3 . ( x- 1/2 )+1/3 = -5/6`

`( x- 1/2 )+1/3 = -5/6 : 2/3`

`( x- 1/2 )+1/3 = -5/4`

` x- 1/2 = -5/4 - 1/3`

` x - 1/2 = -19/12`

`x = -19/12 + 1/2`

`x = -13/12`