Tìm x biết: a) căn16X+16 - căn9x+9 + căn4X+4 + cănX+1 = 16( X -1) b) căn(2x-1)^2 - 1=2

$\text{$\sqrt{16x+16}$-$\sqrt{9x+9}$+$\sqrt{4x+4}$+$\sqrt{x+1}$=16.(x-1)}$

$\text{⇒4$\sqrt{x+1}$-3$\sqrt{x+1}$+2$\sqrt{x+1}$+$\sqrt{x+1}$=16(x-1)}$

$\text{⇒4$\sqrt{x-1}$=16(x-1)}$

$\text{⇒$\sqrt{x-1}$=4(x-1)}$

$\text{⇒$\sqrt{x-1}$=4x-4}$

$\text{⇒($\sqrt{x-1}$)²=(4x-4)²}$

$\text{⇒x-1=16x²-32x+16}$

$\text{⇒x+32x-16x²=16+1}$

$\text{⇒33x-16x²=17}$

$\text{⇒33x-16x²-17=0}$

$\text{⇒\(\left[ \begin{array}{l}x=\frac{17}{16} \\x=1\end{array} \right.\)}$

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$\text{($\sqrt{2x-1}$)²-1=2}$

$\text{⇒($\sqrt{2x-1}$)²=3²}$

$\text{⇒2x-1=9}$

$\text{⇒2x=10}$

$\text{⇒x=5}$