Tìm x: a) $3( 3x - \frac{1}{2})^{3}$ + $\frac{1}{9}$ = 0 b) $2^{x + 2}$ - $2^{x}$ = 96 c) x : $\frac{2}{3}$ - $\frac{2}{3}$ = 0

`a)`
`3( 3x - 1/2 )^3 + 1/9 = 0`
`=> 3( 3x - 1/2 )^3 = 0 - 1/9`
`=> 3( 3x - 1/2 )^3 = -1/9`
`=> ( 3x - 1/2 )^3 = ( -1/9 ) : 3`
`=> ( 3x - 1/2 )^3 = -1/27`
`=> 3x - 1/2 = -1/3`
`=> 3x = -1/3 + 1/2`
`=> 3x = 1/6`
`=> x = 1/6 : 3`
`=> x = 1/18`
 $Vậy$ `x = 1/18`
`b)`
`2^{x+2} - 2^x = 96`
`=> 2^x. 2^2 - 2^x = 96`
`=> 2^x. ( 4 - 1 ) = 96`
`=> 2^x. 3 = 96`
`=> 2^x = 96 : 3`
`=> 2^x = 32`
`=> 2^x = 2^5`
`=> x = 5`
 $Vậy$ `x = 5`
`c)`
`x : 2/3 - 2/3 = 0`
`=> x : 2/3 = 0 + 2/3`
`=> x : 2/3 = 2/3`
`=> x = 2/3. 2/3`
`=> x = 4/9`
 $Vậy$ `x = 4/9`