tìm số nguyên x 1) 2x - ( 35 - x ) = -23 2) 27-3(x-2)=14+2.(1-x) 3) 8x.(9-x)=0

$\text{1) 2x - (35 - x) = -23 Đkxđ: x ∈ Z}$

$\text{2x - 35 + x = -23}$

$\text{3x - 35 = -23}$

$\text{3x = -23 + 35}$

$\text{3x = 12}$

$\text{x = 12 : 3}$

$\text{x = 4 (t/m)}$

$\text{Vậy x = 4}$

$\text{2) 27 - 3(x - 2) = 14 + 2(1 - x) Đkxđ: x ∈ Z}$

$\text{27 - (3x - 6) = 14 + (2 - 2x)}$

$\text{27 - 3x + 6 = 14 + 2 - 2x}$

$\text{-3x + 33 = -2x + 16}$

$\text{-3x + 2x = 16 - 33}$

$\text{-x = -17}$

$\text{x = 17 (t/m)}$

$\text{Vậy x = 17}$

$\text{3) 8x(9 - x) = 0 Đkxđ: x ∈ Z}$

$\text{⇒ 8x = 0 hoặc 9 - x = 0}$

$\text{TH1: 8x = 0}$

$\text{x = 0 : 8}$

$\text{x = 0 (t/m)}$

$\text{TH2: 9 - x = 0}$

$\text{x = 9 - 0}$

$\text{x = 9 (t/m)}$

$\text{Vậy x ∈ {0; 9}}$

$\textit{Ha1zzz}$