2 câu trả lời
\(2^x – 3.\dfrac{2^{(x+2)}}{2} + 8=0\)
\(\Rightarrow 2^x-3.2^{(x+2)-1}+8=0\)
\(\Rightarrow2^x-3.2^{x+1}+8=0\)
\(\Rightarrow2^x-3.2^x.2+8=0\)
\(\Rightarrow2^x-6.2^x+8=0\)
\(\Rightarrow-4.2^x+8=0\)
\(\Rightarrow2^x=2\)
\(\Rightarrow x=1\).
Câu hỏi trong lớp
Xem thêm
