Tìm 3 phân số bằng

a.4/5

b.1/6

c.24/48

Giải giúp các phân số này với ạ cảm ơn

a) $\dfrac{4}{5}$ = $\dfrac{8}{10}$ , $\dfrac{12}{15}$ , $\dfrac{16}{20}$\

b) $\dfrac{1}{6}$ = $\dfrac{2}{12}$ , $\dfrac{3}{18}$ , $\dfrac{4}{24}$

c) $\dfrac{24}{48}$ = $\dfrac{12}{24}$ , $\dfrac{8}{16}$ $\dfrac{1}{2}$

$\text{#Zane#}$

Ta có:

$\dfrac{4}{5}$:

$\dfrac{4}{5}$ = $\dfrac{4×2}{5×2}$ = $\dfrac{8}{10}$

$\dfrac{4}{5}$ = $\dfrac{4×3}{5×3}$ = $\dfrac{12}{15}$

$\dfrac{4}{5}$ = $\dfrac{4×4}{5×4}$ = $\dfrac{16}{20}$

$\dfrac{1}{6}$:

$\dfrac{1}{6}$ = $\dfrac{1×2}{6×2}$ = $\dfrac{2}{12}$

$\dfrac{1}{6}$ = $\dfrac{1×3}{6×3}$ = $\dfrac{3}{18}$

$\dfrac{1}{6}$ = $\dfrac{1×4}{6×4}$ = $\dfrac{4}{24}$

$\dfrac{24}{48}$:

$\dfrac{24}{48}$ = $\dfrac{24÷2}{48÷2}$ = $\dfrac{12}{24}$

$\dfrac{24}{48}$ = $\dfrac{24÷3}{48÷3}$ = $\dfrac{8}{16}$

$\dfrac{24}{48}$ = $\dfrac{24÷4}{48÷4}$ = $\dfrac{6}{12}$