Rút gọn: a) A= $\frac{3}{1.4}$ + $\frac{3}{4.7}$ + $\frac{3}{7.10}$ +...+ $\frac{3}{100.103}$ b) B= $\frac{2}{1.5}$ + $\frac{2}{5.9}$ + $\frac{2}{9.13}$ +...+ $\frac{2}{2021.2021}$ Ví dụ câu a bước đầu là: =3.($\frac{1}{1.4}$ + $\frac{1}{4.7}$ + $\frac{1}{7.10}$ +...+ $\frac{1}{100.103}$ Bước tiếp theo làm thế nào?Câu B làm tương tự giúp mk!!! Nhanh=hay nhất!!!
2 câu trả lời
`a) A = 3/(1 . 4) + 3/(4 . 7) + 3/(7 . 10) + ... + 3/(100 . 103)`
`A = (4 - 1)/(1 . 4) + (7 - 4)/(4 . 7) + (10 - 7)/(7 . 10) + ... + (103 - 100)/(100 . 103)`
`A = 1 - 1/4 + 1/4 - 1/7 + 1/7 - 1/10 + ... + 1/100 - 1/103`
`A = 1 - 1/103`
`A = 102/103.`
`b) B = 2/(1 . 5) + 2/(5 . 9) + 2/(9 . 13) + ... + 2/(2021 . 2025)`
`B . 2 = 4/(1 . 5) + 4/(5 . 9) + 4/(9 . 13) + ... + 4/(2021 . 2025)`
`B . 2 = (5 - 1)/(1 . 5) + (9 - 5)/(5 . 9) + (13 - 9)/(9 . 13) + ... + (2025 - 2021)/(2021 . 2025)`
`B . 2 = 1 - 1/5 + 1/5 - 1/9 + 1/9 - 1/13 + ... + 1/2021 - 1/2025`
`B . 2 = 1 - 1/2025`
`B . 2 = 2024/2025`
`B = 1012/2025.`
`#Staciaa.`
`a) A = 3/( 1. 4 ) + 3/( 4.7 ) + 3/( 7. 10 ) + ... + 3/( 100. 103 ) `
`= (4 - 1)/( 1. 4 ) + (7 - 4)/( 4. 7 ) + ( 10 - 7 )/( 7. 10 ) + ... + ( 103 - 100 )/( 100. 103 )`
`= 4/( 1. 4 ) - 1/( 1. 4 ) + 7/( 4. 7 ) - 4/( 4. 7 ) + 10/( 7. 10 ) - 7/( 7. 10 ) + ... + 103/( 100. 103 ) - 100/( 100. 103 )`
`= 1/1 - 1/4 + 1/4 - 1/7 + 1/7 - 1/10 + ... + 1/100 - 1/103`
`= 1 - 1/103`
`= 102/103`
`b) B = 2/( 1. 5 ) + 2/( 5. 9 ) + 2/( 9. 13 ) + ..... + 2/( 2021. 2025 )`
`B. 2 = 4/( 1. 5 ) + 4/( 5. 9 ) + 4/( 9. 13 ) + .... + 4/( 2021. 2025 )`
`= ( 5 - 1 )/( 1. 5 ) + ( 9 - 5 )/( 5. 9 ) + ( 13 - 9 )/( 9. 13 ) + .... + ( 2025 - 2021 )/( 2021. 2025 )`
`= 5/(1.5) - 1/(1.5) + 9/(5. 9) - 5/(5. 9) + 13/(9. 13) - 9/(9. 13) + ... + 2025/(2021. 2025) - 2021/(2021. 2025)`
`= 1/1 - 1/5 + 1/5 - 1/9 + 1/9 - 1/13 + .... + 1/2021 - 1/2025`
`= 1 - 1/2025`
`B. 2 = 2024/2025`
`B = 2024/2025 : 2`
`B = 1012/2025`
$\text{#lknhatminh0322}$