2 câu trả lời
$\text{PTHH:}$
$\text{MnO$_{2}$+4HCl$\xrightarrow[]{t^o}$MnCl$_{2}$+Cl$_{2}$+2H$_{2}$O}$
$\text{Cl$_{2}$+H$_{2}$$\xrightarrow[]{ánh sáng}$2HCl}$
$\text{Fe+2HCl→FeCl$_{2}$+H$_{2}$}$
$\text{2FeCl$_{2}$+Cl$_{2}$$\xrightarrow[]{t^o}$2FeCl$_{3}$}$
$\text{FeCl$_{3}$+3NaOH→Fe(OH)$_{3}$+3NaCl}$
$\text{2Fe(OH)$_{3}$$\xrightarrow[]{t^o}$Fe$_{2}$O$_{3}$+3H$_{2}$O}$
- `MnO_2``+``4HCl``→``MnCl_2``+``Cl_2↑``+``2H_2O`
- `H_2``+``Cl_2` $\xrightarrow[]{t^o}$ `2HCl`
- `Fe``+``2HCl``→``FeCl_2``+``H_2`
- `2FeCl_2``+``Cl_2` $\xrightarrow[]{t^o}$ `2FeCl_3`
- `FeCl_3``+``3NaOH``→``Fe(OH)_3↓``+``3NaCl`
- `2Fe(OH)_3` $\xrightarrow[]{t^o}$ `Fe_2``O_3``+``3H_2O`
