hoàn thành các pứ sau 1,Na+O2---->Na2O 2 ,AL+CL2---->ALCL 7,K+H2O------>KOH+H2 3,P+O2----->P2O5 4 ,P2O5+H2O----->H3PO4 8,Ca(OH)2+H3PO4------>Ca3(PO4)2+H2 5,AL+HCL------->ALCL3+H2 6,Cu+H2SO4--------.CuSO4 9,Fe2O3 +H2------->Fe+H2O

1.

$4Na+O_{2}\xrightarrow[]{t^o}2Na_{2}O$

2.

$2Al+3Cl_{2}\xrightarrow[]{t^o}2AlCl_{3}$

3.

$4P+5O_{2}\xrightarrow[]{t^o}2P_{2}O_{5}$

4.

$P_{2}O_{5}+3H_{2}O→2H_{3}PO_{4}$

5.

$2Al+6HCl→2AlCl_{3}+3H_{2}$

6.

$Cu+H_{2}SO_{4}\xrightarrow[]{×}$(Không xảy ra phản ứng)

7.

$K+H_{2}O→KOH+\frac{1}{2}H_{2}$

8.

$3Ca(OH)_{2}+2H_{3}PO_{4}→Ca_{3}(PO_{4})_{2}+6H_{2}O$

9.

$Fe_{2}O_{3} +H_{2}→Fe+H_{2}O$

$\text{Đáp án+Giải thích các bước giải:}$

$\text{1 2Na+$O_{2}$→$2Na_{2}O$}$

$\text{2 2Al+$Cl_{2}$→2AlCl}$

$\text{3 4P+$5O_{2}$→$2P_{2}O_{5}$}$

$\text{5 2Al+6HCl→$2AlCl_{3}$+$3H_{2}$}$

$\text{6 Cu+$H_{2}SO_{4}$→$CuSO_{4}$+$H_{2}$}$

$\text{7 2K+$2H_{2}O$→2KOH+$H_{2}$}$

$\text{8 $3Ca(OH)_{2}$+$2H_{3}PO_{4}$→$Ca_{3}(PO_{4})_{2}$+$6H_{2}O$}$

$\text{9 $Fe_{2}O_{3}$+$3H_{2}$→2Fe+$3H_{2}O$}$

$\text{Chúc bạn học tốt}$