hai chu so tan cung cua 2^1000 la; A 06 B 66 C 76 D 86

Đáp án: C

Giải thích các bước giải:

$\begin{array}{l}  + ){2^{1000}} = {2^{20.50}} = {\left( {{2^{20}}} \right)^{50}}\\ {2^{20}} \equiv 76\left( {\bmod 100} \right) \Rightarrow {2^{1000}} \equiv {76^{50}}\left( {\bmod 100} \right)\left( 1 \right)\\  + ){76^{50}} = {76^{5.10}} = {\left( {{{76}^5}} \right)^{10}}\\ {76^5} \equiv 76\left( {\bmod 100} \right)\\  \Rightarrow {76^{50}} \equiv {76^{10}} = {\left( {{{76}^5}} \right)^2} \equiv {76^2} \equiv 76\left( {\bmod 100} \right)\left( 2 \right)\\ \left( 1 \right),\left( 2 \right) \Rightarrow {2^{1000}} \equiv 76\left( {\bmod 100} \right) \Rightarrow C \end{array}$

Đáp án: A. 06