Giải pt sau: $\dfrac{2x+5}{95}$`+`$\dfrac{2x+6}{94}$`+`$\dfrac{2x+7}{93}$`=`$\dfrac{2x+93}{7}$`+`$\dfrac{2x+94}{6}$`+`$\dfrac{2x+95}{5}$ (làm theo cách cộng cả `2` vế với `3` rồi đặt `2x+100` ra ngoài)

`(2x+5)/95+(2x+6)/94+(2x+7)/93=(2x+93)/7+(2x+94)/6+(2x+95)/5`

`<=>(2x+5)/95+(2x+6)/94+(2x+7)/93+3=(2x+93)/7+(2x+94)/6+(2x+95)/5+3`

`<=>(2x+5)/95+1+(2x+6)/94+1+(2x+7)/93+1=(2x+93)/7+1+(2x+94)/6+1+(2x+95)/5+1`

`<=>(2x+100)/95+(2x+100)/94+(2x+100)/93=(2x+100)/7+(2x+100)/6+(2x+100)/5`

`<=>(2x+100).(1/95+1/94+1/93)=(2x+100).(1/7+1/6+1/5)`

`<=>(2x+100).(1/95+1/94+1/93-1/7-1/6-1/5)=0`

Vì

`1/95+1/94+1/93-1/7-1/6-1/5≠0`

`=>``2x+100=0`

`<=>``2x=-100`

`<=>``x=-50`

Vậy `S={-50}`

Pt tương đương :

`(2x+5+95)/95 + (2x+6+94)/94 + (2x+7+93)/93=(2x+93+7)/7 + (2x+94+6)/6 + (2x+95+5)/5`

`<=>(2x+100)/95 + (2x+100)/94 + (2x+100)/93 - (2x+100)/7 - (2x+100)/6 - (2x+100)/5=0`

`<=>(2x+100)(1/95 +1/94+1/93 - 1/7-1/6-1/5)=0`

Do `1/95 +1/94 +1/93 -1/7-1/6-1/5\ne 0`

`<=>2x+100=0`

`<=>2x=-100`

`<=>x=-50`

Vậy `S={-50}`