Giải phương trình sau : 6(x-2)(x-4)(1-7x)=0

Answer

`6 . (x - 2) . (x - 4) . (1 - 7x) = 0`

`=>` $\left[\begin{matrix} x - 2 = 0 \\ x - 4 = 0\\ 1 - 7x = 0\end{matrix}\right.$

`=>` $\left[\begin{matrix} x = 0 + 2 \\ x = 0 + 4\\ 7x = 1 - 0\end{matrix}\right.$

`=>` $\left[\begin{matrix} x = 2 \\ x = 4\\ 7x = 1\end{matrix}\right.$

`=>` $\left[\begin{matrix} x = 2 \\ x = 4\\ x = 1 : 7\end{matrix}\right.$

`=>` $\left[\begin{matrix} x = 2 \\ x = 4\\ x = \dfrac{1}{7}\end{matrix}\right.$

Vậy `S = {2 ; 4 ; 1/7}`