giải phương trình: { 3x-1} {x2+2}={3X-1} {7X -10}

`(3x-1)(x^2+2)=(3x-1)(7x-10)`

`↔(3x-1)(x^2+2)-(3x-1)(7x-10)=0`

`↔(3x-1)(x^2+2-7x+10)-0`

`↔(3x-1)(x^2-7x+12)=0`

`↔\(\left[ \begin{array}{l}3x-1=0\\x^2-7x+12=0\end{array} \right.\)`

`↔\(\left[ \begin{array}{l}3x=1\\(x^2-3x)-(4x-12)=0\end{array} \right.\)`

`↔\(\left[ \begin{array}{l}x=1/3\\x(x-3)-4(x-3)=0\end{array} \right.\)` 

`↔`\(\left[ \begin{array}{l}x=1/3\\(x-3)(x-4)=0\end{array} \right.\)

`↔`\(\left[ \begin{array}{l}x=1/3\\x=3;x=4\end{array} \right.\)