Giải hệ phương trình : $\frac{1}{x+1}$ + $\sqrt[]{4y-8}$ = $\frac{5}{2}$ $\frac{2x}{x+1}$ + $\sqrt[]{9y-18}$ = 4

$\left \{ {{\frac{1}{1+x}+\sqrt[]{4y-8}=\frac{5}{2}} \atop {\frac{2x}{x+1}+\sqrt[]{9y-18}=4}} \right.$

⇔$\left \{ {{\frac{1}{1+x}+\sqrt[]2{y-2}=\frac{5}{2}} \atop {\frac{2x}{x+1}+\sqrt[]3{y-2}=4}} \right.$

⇔$\left \{ {{\frac{1}{1+x}+\sqrt[]4{y-2}=2} \atop {\frac{2x}{x+1}+\sqrt[]3{y-2}=4}} \right.$

⇔$\left \{ {{\sqrt[]{y-2}=1} \atop {\frac{1}{x+1}+2\sqrt[]{y-2}=\frac{5}{2}}} \right.$ 

⇔$\left \{ {{y-2=1} \atop {\frac{1}{1+x}+2.1=\frac{5}{2}}} \right.$ 

⇔$\left \{ {{y=3(tm)} \atop {\frac{1}{1+x}=\frac{1}{2}}} \right.$ 

⇔$\left \{ {{x+1=2} \atop {y=3}} \right.$ 

⇔$\left \{ {{x=1} \atop {y=3}} \right.$