$Fe_aO_b$ $+$ $HNO_3$ $ →$ $Fe(NO_3)_3$ $+$ $N_xO_y$ $+$ $H_2O$
1 câu trả lời
FeaOb + HNO3 → Fe(NO3)3 + NxOy + H2O
Fe(+2b/a) → Fe(+3) + (3-2b/a)e = [(3a - 2b)/a]e (1)
N(+5) + (5-2y/x)e = [(5x-2y)/x]e → N(+2y/x) (2)
(1) Fea(+2b/a) → aFe(+3) + (3a-2b)e I x 5x-2y
(2) xN(+5) + (5x-2y)e → Nx(+2y/x) I x 3a-2b
⇒PT :(5x-2y)FeaOb + (18ax-6ay-2bx)HNO3 → (5ax-2ay)Fe(NO3)3 + (3a-2b)NxOy +
(9ax-3ay-bx)H2O
