Bài 1:Thực hiện phép tính a) -18/27 – 235/971 + 16/24 – 736/971 + 1^2022 c) 24/-36 . 12/19 - 4/6 . 7/19 + 2022^0 Bài 2: Tìm x, biết a) ( x + 3/4 ) . 50% = (-1)^2022 b) x : -22/-33 - 1/2 = 5/6 Mong được giúp ạ!

Đáp án:

$\begin{array}{l}
1)a)\dfrac{{ - 18}}{{27}} - \dfrac{{235}}{{971}} + \dfrac{{16}}{{24}} - \dfrac{{736}}{{971}} + {1^{2022}}\\
 = \dfrac{{ - 2}}{3} - \left( {\dfrac{{235}}{{971}} + \dfrac{{736}}{{971}}} \right) + \dfrac{2}{3} + 1\\
 = \left( { - \dfrac{2}{3} + \dfrac{2}{3}} \right) - \dfrac{{971}}{{971}} + 1\\
 = 0 - 1 + 1\\
 = 0\\
c)\dfrac{{24}}{{ - 36}}.\dfrac{{12}}{{19}} - \dfrac{4}{6}.\dfrac{7}{{19}} + {2022^0}\\
 =  - \dfrac{2}{3}.\dfrac{{12}}{{19}} - \dfrac{2}{3}.\dfrac{7}{{19}} + 1\\
 =  - \dfrac{2}{3}.\left( {\dfrac{{12}}{{19}} + \dfrac{7}{{19}}} \right) + 1\\
 =  - \dfrac{2}{3}.1 + 1\\
 = 1 - \dfrac{2}{3}\\
 = \dfrac{1}{3}\\
B2)\\
a)\left( {x + \dfrac{3}{4}} \right).50\%  = {\left( { - 1} \right)^{2022}}\\
 \Leftrightarrow \left( {x + \dfrac{3}{4}} \right).\dfrac{1}{2} = 1\\
 \Leftrightarrow x + \dfrac{3}{4} = 2\\
 \Leftrightarrow x = 2 - \dfrac{3}{4}\\
 \Leftrightarrow x = \dfrac{5}{4}\\
Vậy\,x = \dfrac{5}{4}\\
b)x:\dfrac{{ - 22}}{{ - 33}} - \dfrac{1}{2} = \dfrac{5}{6}\\
 \Leftrightarrow x:\dfrac{2}{3} = \dfrac{5}{6} + \dfrac{1}{2}\\
 \Leftrightarrow x:\dfrac{2}{3} = \dfrac{4}{3}\\
 \Leftrightarrow x = \dfrac{4}{3}.\dfrac{2}{3}\\
 \Leftrightarrow x = \dfrac{8}{9}\\
Vậy\,x = \dfrac{8}{9}
\end{array}$