2 câu trả lời
$7x-\left|3x+1\right|=x+2$
`x<-\frac{1}{3},\ge \-\frac{1}{3}`
$⇔7x-\left|3x+1\right|-x=2$
$⇔6x-\left|3x+1\right|=2$
TH1: $6x-\left(3x+1\right)=2$
$→3x-1=2$
$→3x-1+1=2+1$
$→3x=3$
$→x=3:3$
$→x=1(tm)$
TH2: $6x-\left[-\left(3x+1\right)\right]=2$
$→6x+3x+1=2$
$→9x+1=2$
$→9x+1-1=2-1$
$→9x=1$
$→x=1:9$
$→x=\dfrac{1}{9}(ktm)$
$\text{Vậy x = 1}$
7x-|3x+1|=x+2
|3x+1|=7x-x+2
|3x+1|=6x+2
3𝑥+1−1=6𝑥+2−1
3𝑥=6𝑥+1
3𝑥−6𝑥=6𝑥+1−6𝑥
−3𝑥=1
𝑥=−1/3
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