`\sqrt{4-x^2}-x+2=0`

2 câu trả lời

${\sqrt[]{4-x²}-x+2=0}$ ${ĐKXĐ:x \geq 2 }$
${⇔\sqrt[]{4-x²}=x-2}$ 
${⇔4-x²=(x-2)²}$ 
${⇔4-x²=x²-4x+4}$ 
${⇔4-x²-x²+4x-4=0}$ 
${⇔-2x²+4x=0}$
${⇔-2x(x-2)=0}$
${⇔\left[\begin{matrix} -2x=0\\ x-2=0\end{matrix}\right.}$
${⇔\left[\begin{matrix} x=0,ktm\\ x=2,tm\end{matrix}\right.}$

Vậy ${x=2}$

 

#andy

\[\begin{array}{l}
\sqrt {4 - {x^2}}  - x + 2 = 0\\
DKXD:x \ge 2\\
 \Leftrightarrow \sqrt {4 - {x^2}}  = x - 2\\
 \Leftrightarrow 4 - {x^2} = {(x - 2)^2}\\
 \Leftrightarrow 4 - {x^2} = {x^2} - 4x + 4\\
 \Leftrightarrow 4 - {x^2} - {x^2} + 4x - 4 = 0\\
 \Leftrightarrow  - 2{x^2} + 4x = 0\\
 \Leftrightarrow  - 2x(x - 2) = 0\\
 \Leftrightarrow \left[ \begin{array}{l}
 - 2x = 0\\
x - 2 = 0
\end{array} \right.\\
 \Leftrightarrow \left[ \begin{array}{l}
x = 0\left( {KTMDK} \right)\\
x = 2\left( {TMDK} \right)
\end{array} \right.\\
 \Rightarrow x = 2
\end{array}\]

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