(3x-1).(5x-4)=(3x-5).(3x-1)
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2 câu trả lời
Giải thích các bước giải:
`(3x-1)(5x-4)=(3x-5)(3x-1)`
`<=>(3x-1)(5x-4)-(3x-5)(3x-1)=0`
`<=>(3x-1)[(5x-4)-(3x-5)]=0`
`<=>(3x-1)(5x-4-3x+5)=0`
`<=>(3x-1)(2x+1)=0`
`<=>`$\left[\begin{matrix} 3x-1=0\\ 2x+1=0\end{matrix}\right.$
`<=>`$\left[\begin{matrix} 3x=1\\ 2x=-1\end{matrix}\right.$
`<=>`$\left[\begin{matrix} x=1/3\\ x=-1/2\end{matrix}\right.$
Vậy `S={1/3;-1/2}`
` ( 3x - 1 ) . ( 5x - 4 ) = ( 3x - 5 ) . ( 3x - 1 ) `
` ⇔ ( 3x - 1 ) . ( 5x - 4 ) - ( 3x - 5 ) . ( 3x - 1 ) = 0 `
` ⇔ ( 3x - 1 ) . [ ( 5x - 4 ) - ( 3x - 5 ) ] = 0 `
` ⇔ ( 3x - 1 ) . ( 5x - 4 - 3x + 5 ) = 0 `
` ⇔ ( 3x - 1 ) . ( 2x + 1 ) = 0 `
` ⇔ ` $\left[\begin{matrix} 3x - 1 = 0 \\ 2x + 1 = 0 \end{matrix}\right.$
` ⇔ ` $\left[\begin{matrix} 3x = 1 \\ 2x = -1 \end{matrix}\right.$
` ⇔ ` $\left[\begin{matrix} x = \dfrac{1}{3} \\ x = \dfrac{-1}{2} \end{matrix}\right.$
Vậy ` S = { 1/3 ; [ -1 ] / 2 } `