2√27 - 6√1/3 + 1/2+√3 - 9/√3

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`2\sqrt{27}-6\sqrt{1/3}+1/(2+\sqrt{3})-\frac{9}{\sqrt{3}}`

`=2\sqrt{3^2 .3}-\frac{6.\sqrt{1}}{\sqrt{3}}+\frac{2-\sqrt{3}}{(2-\sqrt{3})(2+\sqrt{3})}-\frac{3\sqrt{3}.\sqrt{3}}{\sqrt{3}}`

`=6\sqrt{3}-\frac{2\sqrt{3}.\sqrt{3}}{\sqrt{3}}+\frac{2-\sqrt{3}}{4-3}-3\sqrt{3}`

`=6\sqrt{3}-2\sqrt{3}+2-\sqrt{3}-3\sqrt{3}`

`=2`

Đáp án:

`2` 

Giải thích các bước giải:

`2sqrt27-6sqrt(1/3)+1/(2+sqrt3)-9/sqrt3`

`=2sqrt(9*3)-6*sqrt3/3+(2-sqrt3)/[(2-sqrt3)(2+sqrt3)]-(9sqrt3)/3`

`=2*3sqrt3-2sqrt3+(2-sqrt3)/(4-3)-3sqrt3`

`=6sqrt3-2sqrt3+2-sqrt3-3sqrt3`

`=2`.