2 câu trả lời
Đáp án:
0.
Giải thích các bước giải:
$\left(\dfrac{12}{61}-\dfrac{31}{22}+\dfrac{14}{91}\right)\!\!\left(\dfrac12-\dfrac13-\dfrac16\right)\\=\left(\dfrac{12}{61}-\dfrac{31}{22}+\dfrac{14}{91}\right)\!\!\left(\dfrac36-\dfrac26-\dfrac16\right)\\=\left(\dfrac{12}{61}-\dfrac{31}{22}+\dfrac{14}{91}\right)\!\!.0\\=0$
`(12/61-31/22+14/91).(1/2-1/3-1/6)`
`= (12/61-31/22+14/91).(3/6-2/6-1/6)`
`= (12/61-31/22+14/91).0`
`= 0`
#Huy