1 quả cầu đặc bằng sắt có thể tích 200cm3,có khối lượng riêng là 7800 kg/m3 . Tính khối lượng riêng của quả cầu

2 câu trả lời

Đáp án:

 d=78000N/m³

Giải thích các bước giải:

Tóm tắt:

D=7800kg/m³

V=200cm³=0,0002m³

 Có 2 cách để ta tính trọng lượng riêng của quả cầu:

+ Cách 1: Tính gián tiếp

Trọng lượng của quả cầu là:

\[P = 10m = 10.D.V = 10.7800.0,0002 = 15,6N\]

Trọng lượng riêng của quả cầu là:

\[d = \frac{P}{V} = \frac{{15,6}}{{0,0002}} = 78000N/{m^3}\]

+ Cách 2: Tính trực tiếp:

\[d = 10D = 10.7800 = 78000N/{m^3}\]

 

Đáp án:

 Chúc bạn học tốt!!!!!!!!

Giải thích các bước giải:

Đổi V=200cm³=0,0002m³

  Khối lượng của quả cầu là

           m=D.V=7800.0,0002=1,56(kg)

⇒P=10m=15,6N

Trọng lượng riêng của qur cầu là

          d=P÷V=15,6÷0,0002=78000N/M³

Câu hỏi trong lớp Xem thêm

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