Tìm x thỏa mãn:

\(\frac{{x + \frac{3}{2}}}{6} = \frac{{ - 5}}{{12}}\)

\(\frac{5}{{21}}\)

\(\frac{2}{7}\)

\(\frac{{23}}{{21}}\)

\(\frac{{-23}}{{21}}\)

0

\(\frac{4}{9}\)

\(\begin{array}{l}\frac{{ - 4}}{3}\\\end{array}\)

\(\frac{{ - 68}}{{75}}\)

Là số nguyên âm        

Là số nguyên dương

Là số hữu tỉ âm

Là số hữu tỉ dương

$\dfrac{3}{2}$

$ - \dfrac{3}{2}$

$\dfrac{2}{3}$

$ - \dfrac{2}{3}$

\(\frac{{194}}{{45}}\)

\(3\frac{3}{5}\)

\(\frac{{ - 14}}{5}\)

\(\frac{{ - 85}}{{59}}\)

\(\frac{{16}}{{25}}\)

\(\frac{{ - 19}}{{25}}\)

\(\frac{{19}}{{25}}\)

\(\frac{{ - 16}}{{25}}\)

\(\dfrac{2}{3} - \dfrac{5}{7}\)

\(\dfrac{1}{{14}} - \dfrac{1}{7}\)

\(\dfrac{1}{2} - \dfrac{5}{7}\)

\(\dfrac{3}{{14}} - \dfrac{5}{{14}}\)