Gieo ba con xúc sắc cân đối, đồng chất. Xác suất để số chấm xuất hiện trên ba con xúc sắc đó bằng nhau là:

\(\Omega  = \left\{ {SS,NN,NS,SN} \right\}\)                      

\(\Omega  = \left\{ {SS,NN,SN} \right\}\)

\(\Omega  = \left\{ {SS,NN} \right\}\)

\(\Omega  = \left\{ {SS,SN} \right\}\)

\(\dfrac{2}{9}\).

\(\dfrac{1}{6}\).

\(\dfrac{7}{{36}}\).

\(\dfrac{5}{{36}}\).

\(9\)

\(18\)

\(36\)

\(39\)

\({\Omega _A} = \left\{ {\left( {1,6} \right);\left( {2,6} \right);\left( {3,6} \right);\left( {4,6} \right);\left( {5,6} \right)} \right\}\)

\({\Omega _A} = \) \(\{ {\left( {1,6} \right);\left( {2,6} \right);\left( {3,6} \right); \left( {4,6} \right);\left( {5,6} \right);\left( {6,6} \right)} \}\) 

${\Omega _A} =$ $ \left\{ {\left( {1,6} \right);\left( {2,6} \right);\left( {3,6} \right);\left( {4,6} \right);\left( {5,6} \right);} \right.\left. {\left( {6,1} \right);\left( {6,2} \right);\left( {6,3} \right);\left( {6,4} \right);\left( {6,5} \right)} \right\}$

${\Omega _A} = $ $\left\{ {\left( {1,6} \right);\left( {2,6} \right);\left( {3,6} \right);\left( {4,6} \right);\left( {5,6} \right);} \right.\left. {\left( {6,6} \right);\left( {6,1} \right);\left( {6,2} \right);\left( {6,3} \right);\left( {6,4} \right);\left( {6,5} \right)} \right\}$

\(2\)     

\(1\)

\(3\)

\(4\)

\(10\)    

\(16\)

\(32\)

\(64\)

\(\dfrac{1}{{18}}\).

\(\dfrac{1}{6}\).

\(\dfrac{1}{8}\).

\(\dfrac{2}{{15}}\).