Giá trị của giới hạn \(\mathop {\lim }\limits_{x \to \sqrt 3 } \left| {{x^2} - 4} \right|\) là:

\(3\).

\(5\).

\( - 1\).

\(2\).

\(\mathop {\lim }\limits_{x \to  + \infty } f\left( x \right) = L\)

\(\mathop {\lim }\limits_{x \to  - \infty } f\left( x \right) = L\)

\(\mathop {\lim }\limits_{x \to {x_0}} f\left( x \right) = L\)

\(\mathop {\lim }\limits_{x \to L} f\left( x \right) = {x_0}\)

\(P = 18\).       

\(P = 12\).        

\(P = 9\).        

\(P = 5\).

\(\dfrac{1}{5}.\)

\(\sqrt 5 .\)

\(\dfrac{1}{{\sqrt 5 }}.\)

\(5.\)

\(S = 13.\)

\(S = 9.\)

\(S = 4.\)

\(S = 1.\)

\(\mathop {\lim }\limits_{x \to {x_0}} \left[ {f\left( x \right) + g\left( x \right)} \right] = L\)

\(\mathop {\lim }\limits_{x \to {x_0}} \left[ {f\left( x \right) + g\left( x \right)} \right] = M\)

\(\mathop {\lim }\limits_{x \to {x_0}} \left[ {f\left( x \right) + g\left( x \right)} \right] = L - M\)                           

\(\mathop {\lim }\limits_{x \to {x_0}} \left[ {f\left( x \right) + g\left( x \right)} \right] = M + L\)