Bất phương trình \(x - 2 > 4,\) phép biến đổi nào sau đây là đúng?

\(\left| {x - 1} \right| = 1\)     

\(\left| x \right| =  - 9\)          

\(\left| {x + 3} \right| = 0\)

\(\left| {2x} \right| = 10\)

\(S = \left\{ x \in R|{x \ge \dfrac{1}{2}} \right\}\)

\(S = \left\{ x \in R|{x \ge  - \dfrac{1}{2}} \right\}\)

\(S = \left\{ x \in R|{x \le  - \dfrac{1}{2}} \right\}\)

\(S = \left\{ x \in R|{x \le \dfrac{1}{2}} \right\}\)

\(2x + 1 > 5\)

 \(7 - 2x < 10 - x\)

\(2 + x < 2 + 2x\)

\( - 3x > 4x + 3\)

\(x = \dfrac{3}{4};\,x = \dfrac{5}{4}\)          

\(x = \dfrac{1}{4};\,x = \dfrac{5}{4}\)             

\(x =  - \dfrac{1}{4};\,x = \dfrac{5}{4}\)          

\(x = \dfrac{1}{4};\,x =  - \dfrac{5}{4}\)

\(\left\{ {\dfrac{5}{2}} \right\}\)       

\(\left\{ {\dfrac{5}{2};\dfrac{2}{3}} \right\}\)

\(\left\{ {\dfrac{5}{2}; - \dfrac{3}{2}} \right\}\)

\(\left\{ {\dfrac{5}{2}; - \dfrac{2}{3}} \right\}\)

 $x \le 13$                      

 $x > 13$                 

$x < 13$

$x \ge 13$