2 câu trả lời
y=√2x−x2DKXD:2x−x2≥0⇔0≤x≤2y′=2−2x2√2x−x2=1−x√2x−x2Choy′=0⇔1−x=0⇔x=1BXD:0−1+2⇒HamsoDB/(1;2),NB/(0;1)
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y=√2x−x2DKXD:2x−x2≥0⇔0≤x≤2y′=2−2x2√2x−x2=1−x√2x−x2Choy′=0⇔1−x=0⇔x=1BXD:0−1+2⇒HamsoDB/(1;2),NB/(0;1)