x(x-2)+x-2=0
<=> (x-2)(x+1)=0
<=> x-2=0 hoặc x+1=0
<=> x=2 hoặc x=-1
Đáp án: $x(x-2)+x-2=0⇔x^{2}-2x+x-2=0⇔x^{2}-x-2=0⇔(x+1)(x-2)=0⇔x=-1 hoặc x=2$
( X - 1) (X + 1)=0
(X-3)(x+5)=0
Choose the best answer.
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