x(x-2)+x-2=0
<=> (x-2)(x+1)=0
<=> x-2=0 hoặc x+1=0
<=> x=2 hoặc x=-1
Đáp án: x(x−2)+x−2=0⇔x2−2x+x−2=0⇔x2−x−2=0⇔(x+1)(x−2)=0⇔x=−1hoặcx=2
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