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Answer
`(x+5) . (2x-3)=0`
`<=>` $\left[\begin{matrix} x + 5 = 0\\ 2x - 3 = 0\end{matrix}\right.$
`<=>` $\left[\begin{matrix} x = 0 - 5\\ 2x = 0 + 3\end{matrix}\right.$
`<=>` $\left[\begin{matrix} x =- 5\\ 2x = 3\end{matrix}\right.$
`<=>` $\left[\begin{matrix} x =- 5\\ x = 3 : 2\end{matrix}\right.$
`<=>` $\left[\begin{matrix} x =- 5\\ x = \dfrac{3}{2}\end{matrix}\right.$
Vậy `S = {-5 ; 3/2}`
$(x+5)(2x-3)=0$
⇔\(\left[ \begin{array}{l}x+5=0\\2x-3=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=-5\\2x=3\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=-5\\x=3/2\end{array} \right.\)
Vậy $S={-5;3/2}$
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