viết PTHH của các phản ứng sau: 1. isobutan + Clo (1:1) 2. 2-metylbutan + Br2 (1:1) 3. n-butan + Clo (1:1) 4. tách 1 phân tử H2 từ n-butan 5. cracking butan 6. propan + Br2 (1:1)

Giải thích các bước giải:

1/.

$isobutan+Clo(1:1)$

PTHH: Sản phẩm chính

$CH_3-CH(CH_3)-CH_3+Cl_2$ $\xrightarrow{as}$ $CH_3-CCl(CH_3)-CH_3+HCl$ 

2/.

$2-metylbutan+Br2(1:1)$

PTHH: Sản phẩm chính

$CH_3-CH(CH_3)-CH_3+Br_2$ $\xrightarrow{as}$ $CH_3-CCl(CH_3)-CH_3+HBr$

3/.

$n-butan+Clo(1:1)$

$CH_3-CH_2-CH_2-CH_3+Cl_2→CH_3-CHCl-CH_2-CH_3+HCl$

hay: $CH_3-CH_2-CH_2-CH_3+Cl_2→CH_3-CH_2-CH_2-CH_2Cl+HCl$

4/.

Tách 1 phân tử $H_2$ từ $n-butan$

PTHH:

$CH_3-CH_2-CH_2-CH_3$ $\xrightarrow[\text{xt}]{t^o}$ $CH_2=CH-CH_2-CH_3+H_2$

Hay: $CH_3-CH_2-CH_2-CH_3$ $\xrightarrow[\text{xt}]{t^o}$ $CH_3-CH=CH-CH_3+H_2$

5/.

$cracking$ $butan$

PTHH:

$C_4H_{10}$ $\xrightarrow{cracking}$ $CH_4+C_3H_6$

$C_4H_{10}$ $\xrightarrow{cracking}$ $C_2H_4+C_2H_6$

$C_4H_{10}$ $\xrightarrow{cracking}$ $C_4H_8+H_2$

$C_4H_{10}$ $\xrightarrow{cracking}$ $C_3H_8+CH_2$

6/.

$propan+Br2(1:1)$

PTHH: Sản phẩm chính

$CH_3-CH_2-CH_3+Br_2$ $\xrightarrow{t^o}$ $CH_3-CHBr-CH_3+HBr$