2 câu trả lời
$\displaystyle\int \dfrac{x^3}{x+1}dx$
$=\displaystyle\int \dfrac{x^3+1-1}{x+1}dx$
$=\displaystyle\int \dfrac{(x+1)(x^2-x+1)-1}{x+1}dx$
$=\displaystyle\int \left( x^2-x+1-\dfrac{1}{x+1}\right)dx$
$=\dfrac{1}{3}x^3-\dfrac{1}{2}x^2+x-\ln|x+1|+C$
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