Tính log1/2⁡2 + 2log1/2⁡1/3 + log1/2⁡3/8

2 câu trả lời

Đáp án:log1/2⁡2 + 2log1/2⁡1/3 + log1/2⁡3/8== log1/2⁡1/12.

 

Giải thích các bước giải:

 log1/2⁡2 + 2log1/2⁡1/3 + log1/2⁡3/8

= log1/2⁡2 + log1/2⁡1/3 + log1/2⁡1/3 + log1/2⁡3/8

= log1/2⁡(2.1/3.1/3 .3/8) = log1/2⁡1/12.

 

            log1/2⁡2 + 2log1/2⁡1/3 + log1/2⁡3/8

 GIẢI : log1/2⁡2 + 2log1/2⁡1/3 + log1/2⁡3/8

= log1/2⁡2 + log1/2⁡1/3 + log1/2⁡1/3 + log1/2⁡3/8

= log1/2⁡(2.1/3.1/3 .3/8) = log1/2⁡1/12.

 

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