Phân tích đa thức thành nhân tử: a) 4x4+4x3-x2-x b) x6-x4-9x3+9x2 c) (xy+4)2-4(x+y)4 d) 4x4+1 e) x4+324 f) x3-x2-x-2 g) x3-9x2+6x+16 h) 6x2-11x+3 i) 2x2-5xy-3y2 k) (x+2)(x+3)(x+4)(x+5)-24 l) x2+2xy+y2-x-y-12

2 câu trả lời

a)4x4+4x3x2x=(4x4+4x3)(x2+x)=4x3(x+1)x(x+1)=x(x+1)(4x21)=x(x+1)(2x1)(2x+1)

b)x6x49x3+9x2=(x6x4)(9x39x2)=x4(x21)9x2(x1)=x4(x1)(x+1)9x2(x1)=x2(x1)[x2(x+1)9]

c)(xy+4)24(x+y)4=(xy+4)2[2(x+y)2]2=(xy+42(x+y)2)(xy+4+2(x+y)2)

d)4x4+1=4x4+4x2+14x2=(2x2+1)(2x)2=(2x2+12x)(2x2+1+2x

)e)x4+342=x4+36x2+34236x2=(x2+18)2(6x)2=(x2+186x)(x2+18+6x)

f)x3x2x2=x38x2x+6=(x38)(x2+x6)=(x2)(x2+2x+4)(x22x+3x6)=(x2)(x2+2x+4)[x(x2)+3(x2)]=(x2)(x2+2x+4)(x2)(x+3)=(x2)(x2+2x+4x3)=(x2)(x2+x+1)

dạo này mik trả lời toàn bị báo cáo thôi chẳng bt ai báo cáo nữa

a)4x4+4x3x2x=(4x4+4x3)(x2+x)=4x3(x+1)x(x+1)=x(x+1)(4x21)=x(x+1)(2x1)(2x+1)b)x6x49x3+9x2=(x6x4)(9x39x2)=x4(x21)9x2(x1)=x4(x1)(x+1)9x2(x1)=x2(x1)[x2(x+1)9]c)(xy+4)24(x+y)4=(xy+4)2[2(x+y)2]2=(xy+42(x+y)2)(xy+4+2(x+y)2)d)4x4+1=4x4+4x2+14x2=(2x2+1)(2x)2=(2x2+12x)(2x2+1+2x)e)x4+342=x4+36x2+34236x2=(x2+18)2(6x)2=(x2+186x)(x2+18+6x)f)x3x2x2=x38x2x+6=(x38)(x2+x6)=(x2)(x2+2x+4)(x22x+3x6)=(x2)(x2+2x+4)[x(x2)+3(x2)]=(x2)(x2+2x+4)(x2)(x+3)=(x2)(x2+2x+4x3)=(x2)(x2+x+1)g)x39x2+6x+16=x3+x210x210x+16x+16=x2(x+1)10x(x+1)+16(x+1)=(x+1)(x210x+16)=(x+1)(x22x8x+16)=(x+1)[x(x2)8(x2)]=(x+1)(x2)(x8)h)6x211x+3=6x29x2x+3=3x(2x3)(2x3)=(2x3)(3x1)i)2x25xy3y2=2x26xy+xy3y2=2x(x3y)+y(x3y)=(x3y)(2x+y) k)(x+2)(x+3)(x+4)(x+5)24=(x+2)(x+5)(x+3)(x+4)24=(x2+7x+10)(x2+7x+12)24=(x2+7x)2+22(x2+7x)+12024=(x2+7x)2+22(x2+7x)+96=(x2+7x)2+6(x2+7x)+16(x2+7x)+96=(x2+7x)(x2+7x+6)+16(x2+7x+6)=(x2+7x+6)(x2+7x+16)l)x2+2xy+y2xy12=(x+y)2(x+y)12=(x+y)24(x+y)+3(x+y)12=(x+y)(x+y4)+3(x+y4)=(x+y4)(x+y+3)

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