Lim(35479^200+N^3*42-100+7890=X LIM(10000^200+N*4000=X LIM(1000^200+3000)*n+cos1234-sin200=x
1 câu trả lời
$x=\lim(35479^{200}+n^3.42-100+7890)$
$=n^3.\Big(\dfrac{35479^{200}}{n^3}+42-\dfrac{100}{n^3}+\dfrac{7890}{n^3}\Big)$
$=+\infty.(0+42-0+0)$
$=+\infty$
$x=\lim(10000^{200}+4000n)$
$= \lim n\Big(\dfrac{10000^{200}}{n}+4000\Big)$
$=+\infty.(0+4000)$
$=+\infty$
$x=\lim[(1000^{200}+3000)n+\cos1234-\sin200]$
$=\lim n[\dfrac{1000^{200}+3000}{n}+\dfrac{\cos1234}{n}-\dfrac{\sin200}{n}]$
Có $\cos1234; \sin200=const$
$\Rightarrow x=+\infty$
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