Gly – Ala + HCl → Ala-Gly + NaOH → Tinh bột + H2O → Saccarozo + H2O → Alanin + KOH → CH3-CH(NH2)- COOH + HCl → Glyxin + C2H5OH → Buta-1,3-đien → Cao su buna → Tripanmitin + H2O → Metyl axetat + NaOH → Mong mọi người giúp mình ạ

Đáp án + giải thích các bước giải:

Gly `-` Ala `+2HCl+H_2O \to ` Gly`-HCl+` Ala`-HCl`

Ala `-` Gly `+2NaOH \to` Ala`-Na+` Gly`-Na+2H_2O`

$(C_6H_{10}O_5)_n+nH_2O\xrightarrow{H^{+}}nC_6H_{12}O_6$

$C_{12}H_{22}O_{11}+H_2O\xrightarrow[]{H^{+}}C_6H_{12}O_6+C_6H_{12}O_6$

`H_2NCH(CH_3)COOH+KOH \to H_2NCH(CH_3)COOK+H_2O`

`CH_3CH(NH_2)COOH+HCl \to H_2NCH(NH_3Cl)COOH`

`H_2NCH2OOH+C_2H_5OH \to H_2NCH_2COOC_2H_5+H_2O`

$nCH_2=CH-CH=CH_2\xrightarrow[]{t^o;xt;p}(\kern-6pt- CH_2-CH=CH-CH_2 -\kern-6pt)_n$

$(C_{15}H_{31}COO)_3C_3H_5+3H_2O \to\buildrel{{H_2SO_4;t^o}}\over\rightleftharpoons 3C_{15}H_{31}COOH+C_3H_5(OH)_3$

`CH_3COOCH_3+NaOH \to CH_3COONa+CH_3OH`