giúp e ạ cần gấp:(2x-3)(5x+1)=(3-2x)(x-5)

`(2x-3)(5x+1)=(3-2x)(x-5)`

`<=> 10x^2 - 13x - 3 = -2x^2 + 13x - 15`

`<=> 10x^2 + 2x^2 -13x - 13x - 3 + 15 = 0`

`<=> 12x^2 - 26x + 12 = 0`

`<=> (2x - 3)(3x - 2) =0`

`<=> [(2x-3=0),(3x-2=0):}`

`<=> [(x=3/2),(x=2/3):}`

Vậy `S={3/2 ; 2/3}`

`(2x-3).(5x+1)=(3-2x).(x-5)`

`⇔ (2x-3).(5x+1)=(2x-3).(-1).(x-5)`

`⇔ (2x-3).(5x+1)=(2x-3).(5-x)`

`⇔ (2x-3).(5x+1)-(2x-3).(5-x)=0`

`⇔ (2x-3).(5x+1-5+x)=0`

`⇔ (2x-3).(6x-4)=0`

`⇔ 2x-3=0` hay `6x-4=0`

`⇔ 2x=0+3` hay `6x=0+4`

`⇔ 2x=3` hay `6x=4`

`⇔ x=3/2` hay `x=4/6`

`⇔ x=3/2` hay `x=2/3`

Vậy phương trình có tập nghiệm `S={3/2;2/3}`