Giải phương trình Log×(5×^2-8×+3)-2=0

5×^2-8×+3=x^2;

4x^2-8×+3=0

x=3/2 hoặc x=1/2

$\log_{x}{(5x^2-8x+3)}-2=0$ ĐK: $\left\{ \begin{array}{l} 5x^2-8x+3>0 \\ x>0,x\ne1 \end{array} \right .\Rightarrow \left\{ \begin{array}{l} \left[ \begin{array}{l} x>1\\ x<\dfrac{3}{5} \end{array} \right . \\ x>0,x\ne1 \end{array} \right .\left\{ \begin{array}{l} 01 \end{array} \right .$ $\Rightarrow \log_{x}{(5x^2-8x+3)}=2$ $\Rightarrow 5x^2-8x+3=x^2$ $\Rightarrow \left[ \begin{array}{l} x=\dfrac{1}{2}(tm)\\ x=\dfrac{3}{2} (tm)\end{array} \right .$