Dùng 500 ml dung dịch Potassium hydroxide KOH 0,5 M để hấp thu vừa đủ một lượng khí carbon dioxide CO2. Tính thể tích khí carbon dioxide CO2(đkc) tham gia? Tính nồng độ M dung dịch Potassium carbonate K2CO3có trong dung dich sau phản ứng (xem như thể tích dung dịch không đổi sau phản ứng).

2 câu trả lời

Bạn tham khảo!

Ta có PTHH sau:

$\text{2KOH+CO2$\rightarrow$K2CO3+H2O}$

$\text{a) nKOH=CM.V=0,5.0,5=0,25 mol}$

$\rightarrow$ $\text{nCO2=0,25:2=0,125 mol}$

$\text{a) VCO2=n.22,4=0,125.22,4=2,8 lít}$

$\rightarrow$ $\text{nK2CO3=nCO2=0,125 mol và VK2CO3=VKOH=0,5 lít}$

$\text{b) CM K2CO3=$\frac{n}{V}$=$\frac{0,125}{0,5}$=0,25M}$

#TRANPHAMGIABAO

 

Đáp án:

`V_{CO_2}(đktc)=2,8(l)`

`CM_{K_2CO_3}=0,25(M)`

Giải thích các bước giải:

`V_{KOH}=500(ml)=0,5(l)`

` \to n_{KOH}=0,5.0,5=0,25(mol)`

Phương trình hóa học :

`CO_2+2KOH \to K_2CO_3+H_2O`

Theo PTHH `:n_{K_2CO_3}=n_{CO_2}=\frac{1}{2}.n_{KOH}=\frac{1}{2}.0,25=0,125(mol)`

` \to V_{CO_2}(đktc)=0,125.22,4=2,8(l)`

`V_{dd}=V_{KOH}=0,5(l)`

` \to CM_{K_2CO_3}=\frac{0,125}{0,5}=0,25(M)`

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