CMR: $\frac{D^{i^{2}}[5^{5+2n}]-\frac{1}{D[\frac{3125}{32}.(\frac{5}{2})^{2n}]}-2n}{5}$ $=1$ Thử bấm: $\frac{D^{i^{2}}[5^{293}]-\frac{1}{D[\frac{3125}{32}.(\frac{5}{2})^{288}]}-288}{5}$ $=1$(đúng) Bạn chứng minh nha☺️☺️☺️
1 câu trả lời
`{D^{i^2}[5^{5+2n}]-1/{D[3125/32 * (5/2)^{2n}]}-2n}/5` $\\$ `= {log_2(5^{5+2n})-log_2[3125/32 * (5/2)^{2n}]-2n}/5` $\\$ `= {log_2({5^{5+2n}}/{(5/2)^5 *(5/2)^{2n}})-2n}/5`$\\$ `={log_2({5^{5+2n}}/{(5/2)^{5+2n}})-2n}/5`$\\$`={log_2(2^{5+2n})-2n}/5`$\\$`={5+2n-2n}/5`$\\$`=1` (Luôn đúng) $\\$ (ĐPCM)
Câu hỏi trong lớp
Xem thêm
