Tìm kiếm
Kiến Thùy
2 năm trước

Cho 16g lưu huỳnh trioxit tác dụng với H2O thu được 500ml dung dịch H2SO4 a/ Viết PTHH b/ Tính nồng độ mol dung dịch axit thu được

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miussmiuus
2 năm trước

*Đáp án: 0.4M

*Giải thích các bước giải:

Số mol SO3 đem phản ứng là :

nSO3 =8/80 = 0.1mol

SO3 +H2O =>H2SO4

Theo pt : nH2SO4 =nSO2 =0.1 mol

=>nồng độ mol/l của axit thu đc là : 0.1 / 0.25 =0.4M

Văn Giang
2 năm trước

Đáp án:

Giải thích các bước giải:

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