2 câu trả lời
$CH_{3}COOCH_{2}COOC_{2}H_{5}+2NaOH \xrightarrow {t^o} CH_{3}COONa+HOCOONa+HOCH_{2}COOC_{2}H_{5}$
\(CH_3^{}COOCH_2^{}COO_2^{}H_5^{} + 2NaOH \to CH_3^{}COONa + OH - CH_2^{}COONa + C_2^{}H_5^{}OH\)
\({\text{Ban de y cu 1 goc COO se + voi 1 goc Na }}\)
\({\text{va OH se thay vao goc ben canh O cua - COO - }}\)
\({\text{Vi du CH}}_3^{}COOC_2^{}H_5^{} + NaOH\;{\text{thi COO se lay Na }}\)
\({\text{va C}}_2^{}H_5^{}\;{\text{se lay OH tao ra CH}}_3^{}COONa + C_2^{}H_5^{}OH\)
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