1 câu trả lời
a) \(4x²+x+ \dfrac{1}{16}=(2x)^2+2.2x.\dfrac{1}{4}+{\left({\dfrac{1}{4}}\right)}^2={\left({2x+\dfrac{1}{4}}\right)}^2 \)
b) \(36 - 12y + y²=6^2-2.6.y+y^2=(6-y)^2\)
a) \(4x²+x+ \dfrac{1}{16}=(2x)^2+2.2x.\dfrac{1}{4}+{\left({\dfrac{1}{4}}\right)}^2={\left({2x+\dfrac{1}{4}}\right)}^2 \)
b) \(36 - 12y + y²=6^2-2.6.y+y^2=(6-y)^2\)